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#11 | |
Hold mah beer!
Join Date: Feb 2008
Location: 80 Miles South of Moto Heaven
Moto: 08 R1200GS
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This is what I got
y^x=3y-1 x= (ln(3y-1)/ln(y)) only if y > 1/3 z=3^x+5 z = (3y-1)^(ln(3)/ln(y))+5 So basically we have two equations and 3 unknowns.
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#12 |
Moto GP Star
Join Date: Mar 2008
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#13 | |
Hold mah beer!
Join Date: Feb 2008
Location: 80 Miles South of Moto Heaven
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because without more info there is infinite solutions.
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#14 |
AMA Supersport
Join Date: Nov 2008
Location: Redneck Riviera, FL
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Well the fact that we start with two variables, and only one complete equation means that you cant solve for both variables.
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#15 |
Moto GP Star
Join Date: Mar 2008
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#16 |
Clit Commander
Join Date: Feb 2008
Location: Las Vegas
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Every now and again I like to look in these threads to make myself feel dumb. Success.
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#17 |
Moto GP Star
Join Date: Mar 2008
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#18 | |
Custom User Title
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Location: Central NY
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I'm not "fat." I'm "Enlarged to show texture." Handle every stressful situation like a DOG: If you can't eat it or hump it, pi$$ on it & walk away. |
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#19 |
AMA Supersport
Join Date: Nov 2008
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Sounds like you need to get more info from her before any of us can solve it.
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#20 |
Moto GP Star
Join Date: Mar 2008
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